Kinematics-6

2 Answers

we can see that the angle the vector makes from the vertican from it's point of origin is 45 degrees.

So, the magnitude of it's velocity after 2 seconds=
âˆš(10*1/âˆš2)² + (10.1/âˆš2 - 10*2)²

= 14.736m/s
at an angle taninverse(1-2âˆš2)Â°

UP 0 DOWN 1
Akash Anand Try again ..the correct answer is 10 m/s
Upvote·0· Reply ·2013-05-30 23:21:17
Post on FacebookPost anonymously?

The velocity vector makes an angle 90Â° with the x direction
So, velocity after time 2 sec=âˆš(10*0)+(10*1-10*2)² =10m/s

UP 0 DOWN 1
Akash Anand Answer is correct but approach is wrong, try to understand the situation first.
Upvote·0· Reply ·2013-06-02 23:35:12
Post on FacebookPost anonymously?

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω