1I think it's for confusing you, and to ask its velocity after the '2nd' second? I have no other idea, your solution is correct.
A car starts from rest and accelerates at constant rate in a straight line.In the first second the car covers a distance of 2m.The velocity of the car at the end of second(sec)will be
(a)4.0ms-1 (b)8.0ms-1 (c)16ms-1 (d)None of these
(According to me,
since the body is at rest initially and has uniform acceleration thereafter,
v2-u2=2as
v2=4a (after t=1s)
a=v24
Also,v=u+at
v=v24
v=4ms-1
But the given correct answer is 8 ms-1
where did i go wrong??? )
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10 Answers
1
1057@anik....stop posting "Please Help me out" in every thread....we will help you out.... :P
158even if we use formula of nth sec
s=u+an-12a
2=0+v24-12xv24
2=v24-v28
2=2v2-v28
v2=16
v=4ms-1
@epsilon...pleez explain how u got the solution..
@ketan...i knoe...just 2 signify that i m really unable to get the solution...wont repeat it again though...:P
1057aey bhai....question dekh le....after 2 seconds toh nahi hai na?
11s=u+an-1/2a
here a is acc. and n is the nth sec.
2=1/2a
a=4
now in 2nd sec. the distance traversed is
s=4*2-1/2*4
= 6
now
v2=2as
=48
roughly coming v coming 8
158I think 2 sec hi hai.....
if the question is 2 sec, fir 8 hi answer aata hai