A ball is projected upwards from the foot of a tower. The ball crosses the top of the tower twice after an interval of 6s and the ball reaches the ground after 12s. Calculate the height of the tower.
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1 Answers
1161The best way for doing this question is, Time for going up=time for coming down = 12/2 =6s
Since it crosses the tower two times at the interval of 6s that means, it was at the top of the tower at t=3s first time
So, H= ut+1/2 gt^2
and 2U/g=12
