1.A block of mass m is placed on a smooth wedge of inclination theta.The whole system is accelerated horizontally so that the block does not slip on the wedge. What is the magnitude of force exerted by the wedge on the block ?
2.three rigid rods are joined to form an equilateral triangle ABC of side 1m .three particles carrying charges 20C each are attached to the vertices of the triangle. the whole system is at rest in an inertial frame. the resultant force on the charged particle at A has the magnitude
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2 Answers
62First one...
THe body has no net force downward acting on it.. so it does not come down Vertically
So the net vertical force by the wedge on the body is mg
so R cos θ = mg
R= mg/cosθ
62Second Question
Since the system is at equilibrirm.
Net force = 0
