Laws of Motion

In the system shown in figure all surfaces are smooth. Rod is moved by ext. agent with acceleration 9m/s2 downward vertically. Force exerted by the wedge on the rod is __________ .

Please show the working....

6 Answers

1
injun joe ·

Use constraint equation.

a=a'tan 37

a' is the acceleration of the wedge

1
Bicchuram Aveek ·

Yes I've done upto dat...but they are asking the force...

3
Swastika dutta ·

Is the answer 120N???????????

1
Bicchuram Aveek ·

to all who viewed it.....apply N sin37° = 120 u'll get the answer.

11
Tush Watts ·

Here x is the horizontal displacement of wedge and y is the vertical displacement of the rod.

From the figure tAN A= Y/X
i.e is Y = x tan A
a = Ax tan A ...............where Ax is the horizontal acc of the wedge and Ay is the bvertical acc of the rod.

Now frm the wedge,
Nsin A = M A x
but Ax =a / tan A
Therefore, N sin A = M a / tan A
On putting the values we get N = 200

1
Bicchuram Aveek ·

Yes correct Tushar ....:-)

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