Laws of motion

sir,i think the acc of a and b should be same bcause they r connected by a common string

sir iska answer plz mention kar dijiye.....

Sir,if i consider b and c as a single body of mass total 3kg,then the ans is coming to be 3g/4(acc).i took it as a single body because b and a r connected by a common string

sir,on solving further an equation is coming 3g/2=a+a2;where a is the acc of a and b(same) and a2 is the acc of c.

i think acc b + acc c=acc a

the eqn for finding acc must be:
3g-T =1*a...............(1) (for block b)
T = 1*a....................(2) (for block a)
we get acc 3g/2 m/s² for block a and b
and also the acc block c is =0 because there is no net force acting on it.

Basically we can draw 3 FBDs for 3 different blocks. Assign tensions T₁, T₂, T₃ from top to bottom, T₃ being the tension in the spring. Then the eqns will be...

During equillibrium...
T1 = T2
T2 = T3 + 1g
T3 = 2g

After the string has been cut...
T2 = 1a₁
1g + T3 - T2 = 1a₂
2g - T3 = 2a₃

a₁ = a₂ [ Both connected by same string]

Solving yields a₁ = a₂ = 3g/2 ; a₃ = 0