1max extension occurs when the velocity is same for both the block at a particular instant .......
momentum conservation ....
3 * ( -1 ) + 6 * 2 = 9 * v
v = 1 m/s ->
now conserve energy ...
1/2 * 3 * 12 + 1/2 * 6 * 22 = 1/2 * 9 * 12 + 1/2 * k * x2
x2 = 18/k = 18/200 = 9/100
x = 3/10 m = 30 cm
1wrt CM 3kg moves with 2m/s &6kg with 1m/s
by energy conservation
(1/2)*3*22+(1/2)*6*12=(1/2)*200*x2
x=30 cm
1i am rite too.. wat i wrote previously was value of x2 ... i thot u will find x urself .... now i have edited and wrote the value of x .. spoonfeeding u the final answer ..... :)
11o sorry.. i saw his final ans matched so i did d sum that way... i saw ur final ans was one of the wrong options in the Q, so i didnt c the working. :)
