33yes in these not 75% but 95% one get this and in friction tan-1μ
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A ball of mass m slides down a smooth inclined plane which forms a loooop of radius R.At what height it will leave the track and to what max. height it will rise afterwards
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4 Answers
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writing energy conservation..
mg2R=1/2mv2+mgR(1+cosθ)......
balancing force where it will leave the surface..
mg.cosθ=mv2/R...
From two equations..
cosθ=2/3
so it will leave surface at a height of R(1+cosθ)=5R/3
with velocity.. v=√2gR/3
in the direction shown below..
velocity is making θ with horizintal...
thereafter parabolic path so max ht there is say h
Hence the answer..
:)
1this cos inverse 2/3 is a magic angle.
75% i get this angle.. wenever i do these kinda sums.. !
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