106equilibrium extension = (m1+m2)g/k
Now when m1 is removed,
the new equilibrium extension = m2g/k
and the block starts making SHM with time period = 2Ï€√m2/k and amplitude = m1g/k..
maxm velocity = Aω = A*2Ï€/T = m1g/k*√k/m2 = m1g/√km2
two masses m1 and m2 are suspended together by masslesss spring of spring constant k. when masses are in equilibrium, m1 is removed without disturbing the system
find maximum velocity of m2 during oscillation
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