Centripetal acceleration of a particle of mass m moving in a circular of radius r is 4/r2 . What is the momentum of the particle?
4m/r
4m/√r
2m/√r
2m/r
ans (c)
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6 Answers
1ek aur.......
A thin uniform rod of mass m and length is hinged at the lower end of a level floor and stands vertically. It is now allowed to fall, then its upper end will strike the floor with a velocity given by???????
1ohhhhhhh!!!!!!!!!!1
yeAH..... I HAD NEVER THOT OF CONVERTIN IT A TO V2/R
THANKU!! :)
2ND ONE 2 SEEMS EASY
62mgL/2 = 1/2I ω2
I=mL2/3
mgL/2=1/2 mL2/3 ω2
g=L/3 ω2
ωL=√3gL where L is the height of the gate.
1oh k.... thnx........
so if v wer askd vel of mid - pt ans wud hav bn .5 *√3gL..... rite??