x = 64 * t/√2
120*√2/64= t
t = 15*√2/8
y = 64*15/8 -32*15*15*2/2*64
y =120 - 112.5
y = 7.5ft
Since 7.5<10
Therefore the ball will reach the goal
in a soccer practice session the football is kept at centre of field 40yards from the 10ft high goal post.a goal is attempted by kicking at a speed of 64 ft/s at 45 degree to horizontal.will ball reach goal post.
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2 Answers
Manish Shankar
·2009-04-11 21:44:14
y=xtanθ-gx2sec2θ/2u2
y=x-gx2/u2
at x=40 yards=120 ft
for ball to go inside the goal 0<y<10
find if u lies in this range
virang1 Jhaveri
·2009-04-12 01:19:23