answer is D
Q. A body of mas m is thrown at an angle to the horizontal with an initial velocity vo. Assuming air drag to be negligible,
momentum increment lΔpl that the body acquires during the tth second of its motion is
(A) mg/4 (B) mg/3 (C) mg/2 (D) mg
-
UP 0 DOWN 0 0 3
3 Answers
eureka123
·2009-09-17 20:32:42
Since air drag is negligible=> horz velcoity will be same
only change in vertical momentum
vi=vsinθ=>pi=mvsinθ
vf=vsinθ-gt=>pf=mvsinθ-mgt
l Δp l=pf-pi=mgt
at tth sec. l Δp l=mg