A ball falls vertically onto a floor, with momentum p, and then ball bounces repeatedly. The coefficient of restitution is e. The total momentum imparted by ball to the floor is
A) p(1 + e)
B) p/(1 - e)
C) p(1 + 1/e)
D) p{ (1+e) / (1 - e)}
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3 Answers
11here is the solution to ur question amit....
When a particle goes normal collision with the floor with restitution coefficient e, the speed after collision is e times the speed before collision.
Thus here, the change in momentum for 1st impact is ep - (-p) = p(1 + e),
for 2nd impact it is e(ep) - (-ep) = ep(1 + e) and so on...
Hence the total change in momentum is given by
p(1 + e)[ 1 + e + e2 .............]
= p (1 + e)/ (1 - e)
Hope u got it......