ncert doubts

A trolley of mass 200kg moves with a uniform speed of 36km/h on a frictionless track.A child of mass 20kg runs on the trolley from one end to the other ,10m away,with a speed of 4 m/s relative to the trolley in a direction opposite to its motion,and jumps out of the trolley.What is the final speed of the trolley?How much has the trolley moved from the time the child begins to run??

2 Answers

11
virang1 Jhaveri ·

Conservation of momentum
200*10 + 20*4 = 200*v
2000 + 80 = 200v
2080 = 200v
v = 10.4 m/s

Total time = 10/4 = 2.5sec
S = 2.5*10
S = 25m

11
virang1 Jhaveri ·

is it rite?

Your Answer

Close [X]