1is it 8 kgi assumed m2 has to move with constant velocity
- Utkarsh Agrahari how 2T' =Ma & how a'= 3g ?Upvote·0· Reply ·2019-07-29 00:13:06
The question:-
In the arrangement m1=1kg m2= 2kg. Pulleys are massless and strings are light.For wat value of M the mass m1 moves with constant velocity??
A) 6 kg B) 4 Kg
C)8 Kg D)10Kg
In the 2nd pulley left one is m2 and right one is m1!!!!
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3 Answers
1
1Yes, ans is right but in the question is given m1 moves with constant vel.
1YEs , it is m1 only....
2T'=T {Pulley is Massless }
Let the acceleration of M be ' a '
T=Ma
2T'=Ma.............(1)
alSO acceleration of P1 = a ..........{ Constraint }
2g-T'=2a'
T'-g=a'
From this we have ,
a'=g3
T'=4g3
So m1 is moving up with an acceleration 'g3'
And the pulley is moving down with an acceleration 'a'
If both these acceleration are equal ,m1 will have no apparent acceleration
Putting a=g3 & T'=4g3 in equation (1)
24g3=Mg3
M=8