Newton L of M:-

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The question:-
In the arrangement m1=1kg m2= 2kg. Pulleys are massless and strings are light.For wat value of M the mass m1 moves with constant velocity??
A) 6 kg B) 4 Kg
C)8 Kg D)10Kg

In the 2nd pulley left one is m2 and right one is m1!!!!

#Physics #Mechanics

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3 Answers

aditya ravichandran ·2011-06-27 10:04:15

is it 8 kgi assumed m2 has to move with constant velocity

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Utkarsh Agrahari how 2T' =Ma & how a'= 3g ?
Upvote·0· Reply ·2019-07-29 00:13:06
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Abhishek Das ·2011-06-27 18:34:32

Yes, ans is right but in the question is given m1 moves with constant vel.

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aditya ravichandran ·2011-06-27 22:02:46

YEs , it is m1 only....

2T'=T {Pulley is Massless }
Let the acceleration of M be ' a '
T=Ma
2T'=Ma.............(1)
alSO acceleration of P1 = a ..........{ Constraint }

2g-T'=2a'
T'-g=a'
From this we have ,
a'=g3
T'=4g3

So m1 is moving up with an acceleration 'g3'
And the pulley is moving down with an acceleration 'a'
If both these acceleration are equal ,m1 will have no apparent acceleration

Putting a=g3 & T'=4g3 in equation (1)

24g3=Mg3

M=8

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Newton L of M:-

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