A CHAIN CONSISTING OF 5 LINKS OF MASS 0.1 KG IS LIFTED VERTICALLY WITH A CONSTANT ACCELERATION OF 2.4 m/s^2 .THE FORCE OF INTERACTION BETWEEN THE TOP LINK AND LINK IMMEDIATELY BELOW IT WILL BE :-
1) 6.15 N
2) 4.92 N
3) 9.84 N
4) 2.46 N
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Soumo Sarkar Please Explain !Upvote·0· Reply ·2014-05-12 10:14:53- Soumo Sarkar Your answer is right but how ? Can't understand ......
- Himanshu Giria 0.4*(10+2.4)
- Soumo Sarkar Thanks