24ya,in first case.....
2nd case its free
Find time period of rod in both cases
1)
Rod is hinged about centre...Distance a,b are measured from COM and c distance from point where string is tied
2)
Rod is free to move,The strings are at extremes of rod
-
UP 0 DOWN 0 2 16
16 Answers
1yeah we could combine both o' them to make a better question !
24u cna put 1000 springs and blocks.....but this ques is not by me....
i am still trying to reach its answer
24are u sure there is no term involving k2 ???
vaise i dont have the answer....and on seing ur ans i feel its ok..becoz i am getting something very loong....and am unable to find 2 variables [2]
i will reply soon.....by then if u want to post ur own soln u can....
@thejoker.....had i made this up i would have told that openly..i dont need to hide that dude[1]
1I THINK QUESTION ONE IS NOT OF S.H.M
IF WE ROTATE THE ROD IN A.C.W DIRECTION THEN THERE IS NO ROLE OF K1 AND M1 (THE STRING BECOMES LOOSE AND DO NOT EXERT ANY FORCE)
IF WE ROTATE THE ROD IN C.W DIRECTION THEN THERE IS EFFECTIVE ROLE OF K1 AND M1
49I QUOTE................
""IF WE ROTATE THE ROD IN A.C.W DIRECTION THEN THERE IS NO ROLE OF K1 AND M1 (THE STRING BECOMES LOOSE AND DO NOT EXERT ANY FORCE)""
I do not agree................[2][2][2]
1@subhomoy~~ATGS
I AGREE THAT MOTION IS PERIODIC ((((BUT NOT S.H.M))))
(FOR UNDERSTANDING TRY THIS QUESTION IN PARTS .i.e, WHEN ROD IS CONNECT ONLY WITH ONE OF THREE COMBINATIONS OF STRING AND SPRINGS) IT WILL SHOW THAT IT IS NOT IN S.H.M WITH M1 , M2 , K1 , K2
1subhomoy~~ATGS
SECOND QUESTION IS ALSO NOT FROM S.H.M
lol
lol
ROTATE THE BIGGER ROD IN A.C.W DIRECTION (THE STRING BECOME AGAIN FREE)
49pata hai yaaar..............but how to do these types of sums??????????are we getting these in JEE?????????[17][17][17]
1we don't get any very tough problem in IIT ...
all questions of IIT Entrance are checked at least 100 times by IIT teachers ...
all questions will be conceptual with little calculations....
so don't worry ...we are able to get ranks in top 500...[1][1]