Two point masses m1 and m2 are connected by a spring of natural length l.The spring is compressed such that two point masses touch each other and then they are fastened by a string.Then system is moved with velocity v along the +ve X axis.When the system reached the origin the string breaks (t=0).The position of point mas m1 is given by x1=vt-A(1-cos #t) where A and # are constants.
Find position of second block as a function of time.Also find relation between A and l
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1 Answers
1357x2 should move such that the centre of mass moves through distance vt
(m1x1+m2x2)/(m1+m2)=vt
m2x2=(m1+m2)vt -m1x1=m1vt+m2vt - m1(vt-A(1-cos#t))
=m2vt +m1A(1-cos#t)
x2=vt + (m1/m2)A(1-cos#t)
