(1) A monkey of mass 15kg is climbing on a rope with one end fixed to the ceiling.If it wishes to go up with an acceleration of 1m/s2,how much force should it apply to the rope?If the rope is 5m long and the monkey starts from rest,how much time will it take to reach the ceiling?
(2) A block A can slide on a frictionless incline of angle x & length l,kept inside an elevator going up with uniform velocity v.Find the time taken by the block to slide down the l dist. If it is released from the the top of the incline.
13)Plz anyone explain the meaning of pseudo force.I couldn't understand what actually it means.
11) it tension in the rope be T, then
T - 15g = 15.1
or T=165N
hence the monkey should apply 165N in the downward dirn
2) as the elevator moves with const vel., the frame will be inertial.... so simply writing newton's law,
l = (1/2)(gsinx).t2
11m = 15 kg of monkey. a = 1 m/s2.
T - ( mg + ma) = 0
T – [15g + 15(1)] = 0
T = 15 (10 + 1) T = 15 × 11
T = 165 N.
The monkey should apply 165N force to the rope.
Initial velocity u = 0 ; acceleration a = 1m/s2 ; s = 5m.
s = ut + ½ at2
5 = 0 + (1/2)1 t2
t2 = 5 × 2
t = √10 sec.
Time required is √10 sec.
Please draw the fbd yourself, if you cant then ping me
11The physically apparent but nonexistent force needed by an observer in a noninertial frame to make Newton's laws of motion hold true. The centrifugal force is a pseudo force. Also called fictitious force.
A fictitious force, also called a pseudo force, d'Alembert force or inertial force, is an apparent force that acts on all masses in a non-inertial frame of reference, such as a rotating reference frame. The forces may be treated algebraically like a real force, but the fictitious forces do not necessarily obey Newton's first law.
The force F does not arise from any physical interaction but rather from the acceleration a of the non-inertial reference frame itself. As stated by Iro: "Such an additional force due to nonuniform relative motion of two reference frames is called a pseudo-force."
http://www.answers.com/topic/fictitious-force
21take a book,put a pen on it...now apply some force on the book to produce acceleration..u will see that the pen is moving in the opposite direction WITH RESPECT TO THE BOOK.. [u may think this is because of inertia..but its nt inertia as it is not an inertial reference frame( it is accelerated) n u cant apply newtons law directly here]... so there must be a force which is pushing the pen in opposite direction..the force acting on the pen is nothing but PSEUDO FORCE....
the magnitude of the pseudo force acting on the pen is = mass of the pen* acceleration u gave to the book
if u push the book with uniform velocity u will see that the pen is in rest WITH RESPECT TO THE BOOK,because this is an inertial reference frame...so there is no pseudo force acting on the pen.
u will also see that if u provide smaller acceleration to the book,the pen is in rest W R T BOOK.. that is because here the frictional force between the book and pen ≥ the pseudo force......
hope i explained well :P:P
6well its wrong to think that pseudo force is an additional force........
its just a component of the net force arising in non inertial frames so that newton's laws can be applied in that frame as well.
1well take in the best and i think simplest way
it's just a kind of correctional force that is applied in a non-inertial rame so that newton's continue to hold in that frame