OBJECTVE

5 Answers

1
Sayantan Das ·

The answer is a)

just draw the free body diagram properly and you will be able to solve...

1
JOHNCENA IS BACK ·

YES,SATYAN

POST THE SOLUTION....PLZ

1
Sayantan Das ·

See first of all...
on the block m2 two forces are acting i.e. weight downwards and the tension upwards...
considering just before moving the body is in equilibrium..hence tension(T)=m2g

for the first block four forces are acting weight, tension the normal force from the ground and friction which is static in this case..

the normal component of tension and the normal force will balance the weight..
N=m1g-Tsin45
and horizontally the horizontal component of tension balances the friction(f)=uN...
i.e. Tcos45=uN;
T=m2g;
and Tcos45=u(m1g-Tsin45)...

hence from the two eqns solve for u...
understood????

dude it's Sayantan..!!!!

1
JOHNCENA IS BACK ·

GOT WHERE I WENT WRONG...........I WAS TAKING ACCELERATION TOO..........SO I WAS GETTING THREE EQUATIONS AND FOUR VARIABLES!!!!!!!!!!!!!!!!!!!

1
Sayantan Das ·

yes...there will be no accln as it says as the body just begins to move..!!!

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