Mechanics - physics problem

1

rishabh ·2012-03-26 06:35:21

160 Ï€² cos(4Ï€t)7 ?

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71

Vivek @ Born this Way ·2012-03-26 06:55:25

Nopes!
Approach pleasE?

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1

rishabh ·2012-03-26 08:14:09

acc. of platform = - 32 Ï€² cos(4Ï€t)
=> pseudo force on sphere = 32 Ï€² cos(4Ï€t)
force eqn. of sphere => 32 Ï€² cos(4Ï€t) - f = ma
torque eqn. => f.R = 2/5 mR^2 Î±
a = RÎ±
solving gives tht answer

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71

Vivek @ Born this Way ·2012-03-26 09:14:56

Ohh. I misread the problem. thanks!

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rishabh ·2012-03-26 09:24:45

what's the answer?

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Vivek @ Born this Way ·2012-03-26 09:45:35

- 32/3 Ï€² cos(4Ï€t)

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rishabh ·2012-03-26 10:19:40

what is wrong in my soln. ?

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21

Swaraj Dalmia ·2012-03-26 10:24:21

MI of a cylinder =MR²/2

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rishabh ·2012-03-26 10:25:21

lol! read sphere :P

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Vivek @ Born this Way ·2012-03-27 04:05:28

Does that give correct answer.Don't know wherefrom I'm getting an extra 2 in numerator

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Manoj Srivastava ·2012-04-14 18:50:39

Hi all, get relevant and useful flash animations in physics at http://www.mksfoundation.com/flashlets.aspx
and lot of other free stuff for JEE preparation at this site.

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