A free 238U nucleus kept in atrain emits an alpha particles.When
the train is stationary, a nucleus decays and a passenger measures that the separation between the alpha particle and the recoiling nucleus becomes at time t after the decay.If the decay takes place while the train is moving at a uniform velocity v, the distance between the alpha particle and the nucleus at a time t after the decay as measured by the passenger is:
(A) x+vt (B) x-vt (c) x (D) depends on the direction of the train......
Plese don't post the solvution, only give me some hints...
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2 Answers
hint: what is a non-inertial frame? what is an inertial frame? what is relative velocity?
I think since passenger is inside the train, it does not matters to him whether the train is moving or not.