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A 14.7m high vertical wall is situated at a distance of 19.6m from a person.At what angle with the horizontal should an object be thrown by that personat a speed of 19.6 m/s so that it clears the wall?

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Samarth Kashyap ·2009-06-20 19:24:25

v₀=v_xi + v_yj
v_x=v₀cosÎ¸
v_y=v₀sinÎ¸

at some instant of time t, x=19.6m and y=14.7m

pls forgive me for the bad diagram

x=v_xt
y=v_yt - 1/2gt²

subst. for v_x and v_y.... and solve for Î¸

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