Projectile Motion

JEE Mains Online › Mechanics questions › Projectile Motion

#Physics #Mechanics

UP 0 DOWN 0 1 2
Post on FacebookPost anonymously?

2 Answers

591

Akshay Ginodia ·2014-01-30 03:40:47

Acc. to the 1st graph V_y becomes zero after 1/2 seconds which happens at the highest point
so half the time of flight = usinÎ¸/g = 1/2
so , usinÎ¸ = g/2 = 5 m/s

similarly at x=2 V_y = 0 ,therefore x=2 is half the range..from there u can get it

UP 3 DOWN 1
Sahil Jain ohh!!!second graph gives the range...i didnt see that x there
Upvote·0· Reply ·2014-01-30 03:50:14
Post on FacebookPost anonymously?

591

Akshay Ginodia ·2014-01-29 23:15:37

Y component = 5 m/s
X component = 4m/s

UP 1 DOWN 1
Sahil Jain how
Upvote·0· Reply ·2014-01-30 03:25:17
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω