996the acceleration of train is 5m/s2
A train is moving along a straight line with a constant acceleration a. A boy standing in the train throws a ball forward at an angle of 60° to the horizontal. The boy has to move forward by 1.15m inside the train to catch the ball back at the initial height. The acceleration of the train in ms-2 is?
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2 Answers
996s=ut+1/2at2
0=usin60°t + 1/2*10t2 (vertically)
after substituting the value of u=10m/s and a =10m/s2
we get t =√3 sec
1.15 = 10cos60°√3 - 1/2*a*(√3)2 (horizontally)
a =5m/s2
Soumyadeep Basu How do you get u = 10?Upvote·0· Reply ·2013-02-23 22:50:59
Sourup Nag it was given u= 10, i forgot 2 mention that- Swarna Kamal Dhyawala actually this some was done in class @soumyadeep