relative........

two blocks A and B of mass m and 2m are conncected by a massless spring of force constant k.They are placed on smooth horz. plane.Spring is stretched by an amount x and then released.Calculate relative velocities of blocks when spring comes to original length..

7 Answers

1
dimensions (dimentime) ·

Vrel.=3x√k/(6m)

is thyis the ans ?????

33
Abhishek Priyam ·

yes its 3x√k/6m

with velocity of m as x√2k/3m and of 2m as x√k/6m

62
Lokesh Verma ·

Force acting on the two masses is always equal.. hence.

am = 2a2m

Hence vm = 2v2m

initial potnential energy = 1/2kx2

1/2mvm2+1/2.2m.v2m2

1/2kx2 = 1/2mvm2+1/2.2m.v2m2
1/2kx2 = 1/2 m 4v2m2+1/2.2m.v2m2

1/2kx2 = 3 m.v2m2

1/2kx2/3m = v2m2
v2m= √k/6m x

Relative velocity is v2m +2vm

3x √k/6m

11
Subash ·

concept of reduced mass can be used

1/2(2m/3)(vrel)^2=1/2kx^2

24
eureka123 ·

keeeeep it up subhash.....one line soln..

33
Abhishek Priyam ·

Cheers.. :)

11
Subash ·

thnxxx

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