11
Devil
·2010-01-06 08:28:57
Not too sure...
Since there is no horizontal accn from the external sources, nor any externally appliied torque, the cylinder should continue pure rolling....
However - won't it sink....bcoz r8 when it has even a small part submerged, the wt. of the total cylinder acting downwards, should exceed the buoyant force....
24
eureka123
·2010-01-06 08:55:44
Same thoughts here....rolling should continue...
but maybe the cylinder will suffer a jerk when coming out of fluid ,,,,thats what is worrying me ..
11
Devil
·2010-01-06 08:57:06
I can't actually figure it out nicely....I mean why is the width of that water column given?
24
eureka123
·2010-01-06 09:00:26
one implication may be that at one instant...the full cylinder will be totally inside the tub..only at that instant Bouyant force=weight...at all instants it will vary
1
Philip Calvert
·2010-01-06 09:04:36
first we need to find whether it leaves the first corner or not.
if it doesnt it will simply sink in
bt if it does (which is perhaps much more probable) we need to know how it lands on the other corner
In short , can you specify where did you get this prob, or atleast if it is a subjective one ?
24
eureka123
·2010-01-06 09:07:45
Why wouldnt it leave the first corner??
11
Devil
·2010-01-06 09:15:17
Since buoyant force won't always pass through the cg, it will account for an external torque, which will change the angular velocity, while the linear velocity will definitely be unchanged - thus pure rolling will stop.
24
eureka123
·2010-01-06 09:20:50
looking at whole motion there will be only one point from where impulse will come naa ???? the other corner(right)
11
Devil
·2010-01-08 01:46:20
I didn't look at it like that, only thought abt the last second when the ball is inside the fluid, the centre is out of the fluid but the buoyant force due to the immersed part keeps on acting....that's how it goes....I think.