1taking frame of reference to be at A
velocity of B w.r.t A= 5 m/s downwards
hence omega w.r.t A= 5/a
hence velocity of C in reference to A=
perpendicular to AC and = 5/a*(√2a)=5√2
but C also has a velocity downwards = 5
hence totl velocity = vector sum=(√102+52)
