rotation 2


Three particles A,B,C of mass `m` each are joined to each other by massless rigid rods to form a equilaterall triangle of side `a`.Another particle of mass `m` hits `B` with a velocity v0 directed along BC as shown.
The colliding particle stops immediately after the imapct.

1] Calculate the time required by triangle ABC to complete half revolution in its sub sequent motion.
2]what is the net displacement of point B during this interval?

12 Answers

1
Rohan Ghosh ·

this can be solved by the following steps -
1>locate the centre of mass
2>angular momentum of particle colliding
3>equate it to ang. momentum of the system (Iw)
4>conserve momentum = mv=3mv'
5>then the answer can be obtained

39
Dr.House ·

woh mujhe bi patha hain. tu kar ke dikha mujhe nahin aa raha hain.

1
dimensions (dimentime) ·

is ans to 1st part

t=2√3(pi)a/v0

39
Dr.House ·

dimensions yaar, at first i also arrived at tyhe same answer. its wrong.!!!!!!!!!!!!!!!!

1
Rohan Ghosh ·

hmm i also got the same answer

1
dimensions (dimentime) ·

& of 2nd one

d=(pi)a/√3

not sure

39
Dr.House ·

sorry u are wrong in this opton also.

1
dimensions (dimentime) ·

sahi hai

time galat aa raha hai to displacement to galat hi aayega
i have not read ur previous post !!!!!!!!!!!!

39
Dr.House ·

t=6aΠ/√3v0

s=a[1+(2Π+√3)2]1/2/√3

1
Rohan Ghosh ·

6/√3=2*3/√3=2√3

:)

39
Dr.House ·

ya sorry

forgot maths

1
Rohan Ghosh ·

for the second one
there will be two displacements of B
1> in horizontal direction=just vt
2>in the direction of the diagonal = √(a2+(2a√3/2) )

now their vector sum will give displacement

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