In the fig. shown a smooth ring is connected to rod AB while rod CD passes thru ring . At the given instant angular vel. of rod AB abt hinge A is 1 rad/s and AC=CB. Instantaneous angular vel. of rod CD abt hinge C is
(A) 1 rad/s
(B) 1/2 rad/s
(C) root (3) / 2 rad/s
(D) 3/2 rad/s
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1 Answers
23we just need to find component of vel of pt B _|_ to rod BC wich will be equal to Lω'
where ω' = nag vel of rod BC
so AB(ω)cos30 = BC(ω')
AB = BC√3
so ω' = 3ω/2 = 3/2
