Two bobs of masses 6m and 10m are attached to the two ends of a light inextensible string which passes over a frictionless ring at O. The lighter bob describes a horizontal circle about the heavier bob(which remains stationary at C) as centre. Show that OC= 3a/g where 'a' is the length of the string ant the time period of revolution of the lighter bob is pi*(3a/2g)^(1/2) where 'g' is acceleration due to gravity.
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