24Sir I think we can solve it in this way..............so it wont look out of syllabus........
Torquenet=(1600-400)(0.4)=1200(0.4)=480
&& ω=10π r/s
=>Net power delivered to dynamo=480(10Ï€)=4800Ï€
the driving side of a belt has a tension 1600N and the stock side has 400 N tension The belt turns a pulley 40 cm in radius at the rate of 300 r.p.m. to a dynamo The power delivered is
Please give the solution
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5 Answers
24
62oops yes eureka.. i din look at the full thing.. just saw tension on one and another.. :D
good work..
1i got the solution Thanks
But please explain the driving side and the stock side of the belt What does that mean
62when a belt is rolling, one side is pulling the pulley.. the other is just moving.. the one that is pulling is called the driving side ...