1
Rohan Ghosh
·2009-03-10 08:05:55
Are the answers these ?
1>a
2>a
3-- cannot be seen
here is my process
for the first one
JR=Iw
but w=2Ï€
R=5/2cm=5/2(10-2)m
J=1*sinθ=4/5
replacing the valkues we get the answer
for the second one just complete the prism by turning it into a cuboid
thus now the prism consists of a cuboid and a nagetive mass M
thus
M(32)/12+M(42)/12-I=I
we know the valueof I
thus we get the value of M
33
Abhishek Priyam
·2009-03-10 08:23:29
:)
the main point was to find moi.. :)
1
Philip Calvert
·2009-03-10 08:30:14
[9] maybe he thot it was too mundane to mention
one small thing abhishek......can you help me here
http://targetiit.com/iit_jee_forum/posts/full_test_3_d_3220.html
i know it is some small or silly mistake that i have done
1
Vivek
·2009-03-10 21:28:33
rohan,one doubt,can u explain this
"M(32)/12+M(42)/12-I=I"
1
satan92
·2009-03-11 06:58:05
I think he means if the moment of inertia of the prism is I and we place two prisms side by side then we get moi = 2I but placing two prisms side by side just makes it a cuboid with moi =
Ml2/12 + Mb2/12
thus
2I=Ml2/12 + Mb2/12
as we know I ,l, b we get M ..