A wheel of radius R rolls without slipping with a speed v on a horiz road. When it is at a pt. A on the road , a small mud particle separates frm the wheel at its highest pt. and lands at pt. B on the road . Then
(A) AB = v(R/g)1/2
(B) AB = 2v(R/g)1/2
(C) AB = 4v(R/g)1/2
(D) none of these
plzz give the full soln..
11AKHIL bhai woh 1/2 power ke liye hai na.
Agar ha fhir ans c hoga .
kafi asaan hai .top most point ki velocity 2v hogi (kyonki no slipping diya hai aur w=v/r hoga to topmost point ki velocity=v+R*(v/r))
Ab to simple projectile hai .
2r=1/2gt2
t=(4r/g)1/2
x=2v*t=4v(r/g)1/2
hence c
