s.h.m

a particle of mass 2 kg undergoes s.h.m according to x = 1.5 sin(πt/4 + π/6 ) wat is the shortest time required for the particle to move from x = 0.5 m to x= -0.75 m

9 Answers

1
big looser ......... ·

koi to reply karo

33
Abhishek Priyam ·

bahut hi ganda answer..

(sin-1(1/3)+Ï€/6)*(8/2Ï€)

1
big looser ......... ·

abhi............... tel me the sol

1
chakde ·

SUBSTITUTE X1 FIND T1 ;

REPEAT FOR x2 ; FIND T2

T2-T1 = t = ans....

33
Abhishek Priyam ·

answer sahi hai...[7]

1
big looser ......... ·

don't know about the right answer but mera answer kuj aur hai

1
big looser ......... ·

now i got it............. thanks to both of you

1
big looser ......... ·

answer sin k terms mein nai dia. numerical value di hai 0.28 sec

33
Abhishek Priyam ·

okie..

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