1is the ans is 0.4 sec
a particle is performing simple harmonic motion along x axis with amplitude 4 cm and time period 1.2 s. The min. time taken by particle to move from x=+2 cm to x=+4 cm and back again is_________
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3 Answers
1mohit......the ans given is 0.2 sec but even i got the ans as 0.4s ........so could u do the steps here
1min time is when the particle mean position is at origin so the particle covers an angle of 120 degree in moving from +2 to +4 and back again
covering an angle of 120 degree means , time taken= total time period /3
from there u get the answer