jaldi
for the arrangement shown in figure, the spring is initially compressed by 3 cm. when the spring is released, the block collides with the wall and rebounds to compress the spring again. if the time starts at the instant when the spring is released, find the minimum time after which the block becomes stationary
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6 Answers
big looser .........
·2009-02-05 11:31:06
sorry i forgot to mention.. coeffecient of restitution is 1/√2
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·2009-02-05 11:38:34
1/2 kx^2=1/mv6@
u get v as 300
nw
tym for goin 2 d wall
v=at so
a=300/t
and s=1/2at^2
so 4=1/2( 300/t) t^2
u get t frm here
nw vsepration /v appraoch =e=1/√2
vsep=300/rrot 2
frm heer u get v so nw u can find t then add both d tym