shm

for the arrangement shown in figure, the spring is initially compressed by 3 cm. when the spring is released, the block collides with the wall and rebounds to compress the spring again. if the time starts at the instant when the spring is released, find the minimum time after which the block becomes stationary

6 Answers

1
big looser ......... ·

jaldi

24
eureka123 ·

is collision elastic?????

1
big looser ......... ·

sorry i forgot to mention.. coeffecient of restitution is 1/√2

1
°ღ•๓яυΠ·

1/2 kx^2=1/mv6@
u get v as 300
nw
tym for goin 2 d wall
v=at so
a=300/t
and s=1/2at^2
so 4=1/2( 300/t) t^2
u get t frm here
nw vsepration /v appraoch =e=1/√2
vsep=300/rrot 2
frm heer u get v so nw u can find t then add both d tym

1
big looser ......... ·

TEL ME YOUR FINAL ANSWER

1
°ღ•๓яυΠ·

oyee kuch toh kar yaar woh khud kar diyo

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