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If the total energy of the particle is E, it will perform periodic motion only if :
(A) E < 0 (B) E > 0 (C) V0 > E > 0 (D) E > V0
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3 Answers
Ricky
·2011-03-25 23:49:56
In a S. H . M , the total total energy of a particle is always constant and greater than zero . Hence , the option " ( a ) " is incorrect .
If , " E > V0 " , then , as the paticle possesses greater total energy , so , instead of performing S . H . M , it will tend to go towards infinity .
So , the only possibility is : - V0 > E > 0 .