A block of mass 'M' executes S.H.M. with amplitude 'A'. When it passes through the mean position, a lump of putty of mass 'm' is dropped on it.Find the new amplitude.
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1 Answers
262let the velocity at mean pos. be v m/s
1/2 * k *A2 = 1/2*M*v2 ... (i)
after adding the lump , M' = M+m
from C.O.M ,
Mv =(M+m)v2 ...... (ii)
now new amplitude = A2
1/2*k*A22 = 1/2*(M+m)*v22 ... (iii)
from the above eqns. i) ii) iii) ,
A2 = A √MM+m