1i think this is an hcv question...
1 min posting solution ...
A chain of length l is placed on a smooth spherical surface of radius R. with one of its ends fixed at the top of the sphere.What will be the acceleration ω of each element of the chain when its upper end is released?It is assume that the length of the chain l<πR/2
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15 Answers
1kinetic energy of chain= loss in P.E.
1/2mv2 =mgR2sin-1(l/R)/L - θ∫θ+α mgR2(cosθ)dθ/L
=mgR2sin-1(l/R)/L - mgR2[sinθ]θθ+α/L
=mgR2/L [sin-1(l/R) + sinθ - sin(θ+ l/R)
here this v is tangential..
so ω=v/R :)
1ok then also ...see...
v = [something]
now a=dv/dt ...
u willl get some dθ/dt trem and dat is equal to angular speed..
ang speed= v/r as uusual...
3hey sky can u please solve the problem with force mthd. i have problem in finding the tension of the string.
1yaaaaaaaaaaar tum force method kyun lagaoge ??? [7] [7]
energy se itnaaaaa sundar ho jaara..
y r u trying to work so hard [3]
nishant bhaiya ko bolte hain... [1]
1ok translating.........
friend, u force method why putting?
energy with so beautiful happening!
next line in eng only :P
to nishant bhaiya asking..
[3]
1sry kidding :P
dun do with force method...
y do you think we have learnt energy method ?? :P
[to do these sums ... :P]
62arrey dont worry this is not to be solved by force method..
I dont know of a solution.. and i cant think either..
if at all there is, then i am sure that i dont know it.. and that it will be very tough to solve by that method...