spring again

Two bars f masses m1and m2 connected by a non deformed light spring rest on a horizontal plane. The coefficient of friction between surface and the bodies is μ. What minimum constant force has to be applied in the horizontal direction to the bar of mass m1 in order to shift the bar m2?

(i think question is complete if the diagram is needed then tell )

and do post ur method with ur answer

26 Answers

24
eureka123 ·

my mistake in m1 and m2............corrected it...........

and @ sankara........rethink.....[12]

1
Bicchuram Aveek ·

Why is it not 2μm1g but only μm1g ?

33
Abhishek Priyam ·

Eureka... u are right...in ur soln... :)

in the mean time i will think how to xplain it to u... abhi tak nahi soche kaise xplain karna hai.. [3]

11
Subash ·

im going to guyz

[13]][14]

24
eureka123 ·

now how i am gonna explain u this????[7][7][7]......

i think if u rethink on this one....u will get the concept urself..........in the mean time i will think how to xplain it to u.[3][3][3]

3
msp ·

people pls reply . i was confused with the soln given by eureka.

3
msp ·

the extension of the spring will always be less than tht of the displacement of the block

3
msp ·

but how will the extension of the spring will be equal to the displacement of the block . i think constraint cant be applied.eureka pls reply for my dbt in ur revisons pbms post

11
Subash ·

Actually i took this one from YG file

11
Subash ·

yeah u r rite eureka

answer perfect

philip it is just different language in the question i think

they mentioned bars and just gave the usual blocks [3]

n philip ur method is wrong i dont think this one can be solved without the work energy equation written by eureka

24
eureka123 ·

i dont have hcv dear.......so i dont know about that.............but someone else may know.

1
°ღ•๓яυΠ·

i guess if ma memory wrks well
this is an hcv sum ....frm chap center of mass u'll get d sol der may b in solved eg

24
eureka123 ·

elongation in spring........[1]

11
Subash ·

is it too difficult

or is it too easy

atleast comment on it everyone

3
msp ·

wat is x in ur energy conservation eureka.

24
eureka123 ·

i hope its okay now......

11
Subash ·

okk eureka now got itt thankks [1]

3
msp ·

eureka i think ur rong in the energy conservation. i found it rong becos of the x term can u explain

11
Subash ·

ans should be in terms of μ m1, m2, and g

@eureka can u explain ur second equation with works im not getting it

24
eureka123 ·

x ki value apne aap daal lena yaar.............concept aur ans yehi hai.....[1][1]

11
Subash ·

@philip i should have given diag earlier sorry

to have caused the confusion with bars

11
Subash ·

guyz sorry if it was confusing without diag

11
Subash ·

diag coming up!edited to coming down [3]

3
msp ·

for the second block

μmg≤kx

for the first block

F-μmg=kx1

but x is < x1

so 2μg<F

know this is rong. but this is the thing dat i got.pls correct me guys.

1
Philip Calvert ·

hmmm...

why have u used rods even two blocks wud give same result.....

if no then plz post diagram

@eureka quickly check my answer in your questions thread

24
eureka123 ·

diag bhi de do yaar.....visualize nahin ho paa raha.[2]

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