A bar of cross section A is subjected to equal and opposite tensile forces at its ends! consider a plane through the bar making an angle A with a plane at right angles to the bar. For what values of A is the shearing stress maximum?
A.)30
B.)60
C.)45
D.)75
All angles are in degrees!!!!!!!!!!!
3SHEARING STRESS=
Fcosθsinθ/A................
if that plane is variable then we can find in which plane the stress is max........
Fsin2θ/2A...........
max value is when 2θ = pi/2............
θ = pi/4!!!!!!!!!!!!!!!!!!!!
has been done before in eurekas revision questions!!!!
24yup..............it is an ex-question..........using that effective area concept.......
1Forces are applied on both eds of the bar Then if we take components of both the forces along the required plane won't the net force becomes zero
Please explain
6
considering this figure can you please explain it!
i was getting it to be 75 degree!
as if we consider the shearing force it will be F sin(theta)
and the effective are will come parallel to the force as Fsec(theta)
this gives us Ftan(theta)
hence the answer should be D but the answer is C
1here you are taking normal forces while according to the question they are tensile forces i.e. they are along the cross section os rod
