wats the answer manipal?
Q1 A heavy body of mass 10 kg is to be dragged along a horizontal plane(μ=1/√3).The least force required is
a) 50/√3 N
b) 100/√3 N
c) 50 N
d) 100 N
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15 Answers
Aditya
·2009-04-09 09:51:51
haha....this was a very confusing question...everyone gave the answer wrong except the creator of the test....!!!
vector
·2009-04-09 09:55:44
no virang visit d test sectionmechanics der is a test created by rkrish u ll get ur mistake
Subash
·2009-04-09 10:07:24
F cos θ = μ (mg - F sin θ) => F = μmg/(cos θ + μsin θ)
For least force dF/dθ = 0
dF/dθ = 0 => - sinθ + μcos θ = 0
=> tan θ = μ = 1/√3 => θ = 30°
F = (1/√3).100 / [ √3/2 + 1/(2√3) ] = 50 N
Subash
·2009-04-09 10:08:03
it is directly the solution of rkrish
hope he doesnt have copyright problems [3]