the famous box on inclined plane ... rotational motion problem...

A block with a square base measuring a x a & height h is placed on an inclined plane of angle \Theta . The coefficient of friction is \mu
The angle of the incline is gradually increased. The block will::

a) topple before sliding if \mu > ah

b) topple before sliding if \mu < ah

c) slide before toppling if \mu > ah

d) slide before toppling if \mu < ah

plzzzz in this problem explain from the basics....
plz explain why the normal reaction shifts , due to which torque etc....!!!!!

fig given is

4 Answers

1
pranav ·

is it multiple choice na ??? vise is one answer (A)??

11
SANDIPAN CHAKRABORTY ·

yes

11
SANDIPAN CHAKRABORTY ·

sum1 plz try

1
Tapas Gandhi ·

A,D

f=μmgcosθ
N=mgcosθ

Torque due to f:
μmgcosθh

Torque due to N: (to counter balance torque due to f, N shifts towards left)
mgcosθa

Toppling:
μmgcosθh>mgcosθa
μ> a/h

Sliding:
μ<a/h

Your Answer

Close [X]