torque

a cubical block of mass m and edge a slides down a rough inclined plane of inclination @ with a uniform speed.find the torque of normal force acting on the block about its centre.

5 Answers

106
Asish Mahapatra ·

Concept:
As the friction force will produce a torque, there should be an equal and opposite torque to balance it to prevent toppling.
Who can apply this torque?
Consider all the forces,
weight mg.. (this can't because it always acts AT COM)
friction (this has already created a torque which is to be balanced)
normal reaction (this is the only force left)

So, the normal reaction N will shift its position and will not pass through COM. This will create the equal and opposite torque to balance the torque by friction.

frictional force = mgsin@
torque due to friction = mgsin@*a/2 (abt COM)
so torque due to N = torque due to friction in opposite direction = mgasin@/2

106
Asish Mahapatra ·

1
JOHNCENA IS BACK ·

THANX.........ASHISH

I ALSO THOUGHT SAME BUT WAS NOT SURE AS I SOLVED SUCH A QUESTION FOR FIRST TIME

106
Asish Mahapatra ·

one mistake in the diagram though

THE NORMAL REACTION SHUD SHIFT TO THE OTHER SIDE NOT THE SIDE IVE SHOWN IT. THATS BECAUSE AS I SHOWD, THE TORQUE HELPS FRICTIONAL TORQUE INSTEAD OF BALANCING IT

1
JOHNCENA IS BACK ·

@ashish

yes.............i noticed that but there is no point in pointing out that mistake as if N wud be as in diagram it will help in toppling............

but neways basic thing is revealed..........

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