Mechanics - trouble....

1

harsh jindal ·2010-02-11 09:01:18

are these correct

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rahul nair ·2010-02-11 10:27:57

thnx dude.......

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harsh jindal ·2010-02-11 10:26:07

3) after every 8L/v time the initial velocities are regained
also at these times x coordinate is same as their initial x coordinate

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1

rahul nair ·2010-02-11 10:20:26

A3..How??

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harsh jindal ·2010-02-11 10:19:39

the answer of 3 is
at t=200L/v
velocity of block A is 0
velocity of block B is v( j )

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24

eureka123 ·2010-02-11 10:16:10

thx harsh.,..[1]

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rahul nair ·2010-02-11 09:58:30

kk...thnx

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harsh jindal ·2010-02-11 09:52:17

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rahul nair ·2010-02-11 09:39:45

can u post ur complete working???

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harsh jindal ·2010-02-11 09:36:39

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harsh jindal ·2010-02-11 09:07:02

at t=L/v string becomes intantaneously tight and it behaves like collision and parallel component of velocities of A & B (parallel w.r.t string ) are interchanged and string again start becoming lose

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24

eureka123 ·2010-02-05 20:34:27

anyone ??

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1

madhumitha harishankar ·2010-02-11 09:00:14

harsh,can u explain please?

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harsh jindal ·2010-02-11 08:59:04

ANSWER IS
1) COORDINATES OF BLOCK A (.5L ,.5L)
COORDINATES OF BLOCK B (.5L,1.5L)
2) VELOCITY OF BLOCK A = 12(i + j)
VELOCITY OF BLOCK B = 12(-i + j)

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24

eureka123 ·2010-02-11 08:35:25

?????

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eureka123 ·2010-02-09 21:58:16

no one ????????????

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1

pranav ·2010-02-09 20:39:08

someone do it plzz?

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49

Subhomoy Bakshi ·2010-02-09 09:06:05

hw cn it be taughty???

strng length is L√2 but distance is L <l√2

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pranav ·2010-02-09 08:59:35

the string is taught initially ??? bcoz in diag its not is it taught/?

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24

eureka123 ·2010-02-09 08:52:11

ans1=(L/2,L/2)
ans2=-v/2 i +v/2 j
ans3=v j

plz reply .............

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106

Asish Mahapatra ·2010-02-05 20:43:19

Q2.Q3 V_b = 3v/4 j - v/4 i
V_a = v/4 (i+j) ??

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