262P\hat{i} + 2P\hat{j} + 3P(-\hat{i}) + 4P(-\hat{j}) = - (2P\hat{i} + 2P\hat{j})
\left| - (2P\hat{i} + 2P\hat{j})\right| = 2\sqrt{2}P
PS : you cannot find resultant force since the directions are not specified . only magnitude can be found .
Four forces of magnitude P,2P,3P and 4P act along the four sides of square ABCD in cyclic order.Use the vector method to find the resultant force.
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4 Answers
262
71Aditya, By polygon law of vector addition, shouldn't the resultant be zero?
262the forces have directions as that of the sides of a square,
but since their magnitudes are not same they will not exactly cancel out each other .
158ya....the correct answr given is 2√2P....and the force is acting at an angle of 225° wen measured from positive x-axis.