points A ,B,C,D,E are having equal displacement
xE-xA=λ=4*15=60cm
as λ=2l/n=2 *120/n=60
n=4
so it corresponds to 4th harmonic
(distance of node from A =7.5CM as distance bet. B and C is 15 cm and node is between them .....)
taking node as origin and thus a=A sinkx
here a=3.5mm;k=2Π/λ and x=7.5cm
hence calculate A .................