Waves are confusing....

A large cylinder has an acoustic source at it's base....A small man is sitting at a corner of the cylinder and at time t=0 starts moving towards the source.... - he thereby detects a frequency f_0...Now the chamber is heated isobarically (Process1)....then brought back to it's original state and then hetaed isochorically (Process-2).

1) Frequency detected by the man in P-!
i) >f0 ii)<f0 iii)=f0 iv) Data insufficient.

2) Frequency detected in P-2 :-

Same options.

I'm getting iv) for both.....bcoz in both the processes we have the eqns V=KT & P=KT......we don't know whether temperature is increasing or not.....but answers given are different.....

5 Answers

1
Anirudh Kumar ·

bhaiya

can we say that the container should be closed(assuming)

volume is constant . while heating the gas isobarically the amount of heat absorbed is equal to released by the gas . so, no net increase in temp.

while in isochoric process temp. increases.

24
eureka123 ·

Shouldnt the frequncy remain same ???

11
Devil ·

No eure - it velocity of sound depends on temperature....so doppler frequency changes!

24
eureka123 ·

well ya velcoity depends upon temp and so does wavelngth.....

i have read that freqncy is property of source..and hte only condns when it can change is relative motion b/w source and observer..

btw what are the answers??

11
Devil ·

But doppler effect eure - this frequency is not the actual frequency of the source, it is the frequency as received by yhis unfortunate man in the cylinder.....

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