waves

in dc pandey
it is writen there is no difference between waves represented by the equations

y=Asin(wt-kx)
and
y=Asin(kx-wt)

thats easy
now we know the difference is that one is moving downwards and other is moving upwards

now i want to know which is moving upwards

in dc pandey it is written by Asin(kx-wt) this one is moving upwards

but when u differnetiate it to find the vel it is coming negative so this wave shoud move downwards and other should move upwards

what is the flaw in my logic

3 Answers

106
Asish Mahapatra ·

how are you differentiating it? as it contains two variables.

Let us take y=Asin(kx-wt)

at t=0, the shape of the curve is y=Asinkx at x=0, the disp is zero

Now v of any particle = ∂y/∂t = -Awcos(kx-wt)

At t=0, v = -Awcoskx
vel of the particle at x=0 is -Aw i.e. it is moving downward

by Asin(kx-wt) this one is moving upwards

u need to get the time intervals and the position of the particle you are talking about.

AT any instant of time there will be some particles moving upward, some particles moving downward and some at rest..

btw hows the prep for NSEP going on?? completed everything??

1
varun.tinkle ·

thats i ashish
it is written in dc pnadey
that the particle at x=0 will move upwards but i dont think so and u also calculatd that vel will be -ve

1
varun.tinkle ·

thats it xyz
in dc pnadey it is writtent ht eparticle at position x=0 will move upwards

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